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常见 三角函数 问题
cos(x-45)=0
cos
(
x
−
4
5
◦
)
=
0
7tan^2(x)-15=0
7
tan
2
(
x
)
−
1
5
=
0
1+cos^2(x)-2cos^2(x/2)=0
1
+
cos
2
(
x
)
−
2
cos
2
(
x
2
)
=
0
2cos^2(x)+5sin(x)=5
2
cos
2
(
x
)
+
5
sin
(
x
)
=
5
(h(sin^2(x)))/((cos(x)-1))=0
h
(
sin
2
(
x
)
)
(
cos
(
x
)
−
1
)
=
0
cos(a)=(-3)/5
cos
(
a
)
=
−
3
5
cos(x)+sin(x-1)=0
cos
(
x
)
+
sin
(
x
−
1
)
=
0
sin^{22}(x)= 1/2
sin
2
2
(
x
)
=
1
2
cos^5(x)=cos(x)
cos
5
(
x
)
=
cos
(
x
)
tan(x)=((1.8)/(3.6))
tan
(
x
)
=
(
1
.
8
3
.
6
)
sec(x+30)=2
sec
(
x
+
3
0
◦
)
=
2
solvefor y,arccos(y/2)=5log_{10}(x/5)
solvefor
y
,
arccos
(
y
2
)
=
5
log
1
0
(
x
5
)
sin^{22}(x)= 1/4
sin
2
2
(
x
)
=
1
4
3sin(2x)-cos(x)=0
3
sin
(
2
x
)
−
cos
(
x
)
=
0
2cos^2(x)+tan^2(x)=2
2
cos
2
(
x
)
+
tan
2
(
x
)
=
2
sin^3(o)=4sin(o)sin^2(o)sin^4(o)
sin
3
(
o
)
=
4
sin
(
o
)
sin
2
(
o
)
sin
4
(
o
)
cos^2(x)=-4
cos
2
(
x
)
=
−
4
8sin^4(x)-6sin^2(x)+1=0
8
sin
4
(
x
)
−
6
sin
2
(
x
)
+
1
=
0
4sin^2(x)+2cos(x)+a=3
4
sin
2
(
x
)
+
2
cos
(
x
)
+
a
=
3
cos^5(x)+cos(x)+4cos^2(x)=2
cos
5
(
x
)
+
cos
(
x
)
+
4
cos
2
(
x
)
=
2
sin^2(x)-sin(x)+2cos^2(x)=1
sin
2
(
x
)
−
sin
(
x
)
+
2
cos
2
(
x
)
=
1
(sin^3(x))/(2+2(sin(x))^2)=1
sin
3
(
x
)
2
+
2
(
sin
(
x
)
)
2
=
1
solvefor x,cot^2(x)= 1/3
solvefor
x
,
cot
2
(
x
)
=
1
3
2+cos^2(x)=-5sin(x)
2
+
cos
2
(
x
)
=
−
5
sin
(
x
)
tan^5(x)tan^2(x)=1
tan
5
(
x
)
tan
2
(
x
)
=
1
(sin^2(a)+1)/((1+tan^2(a)))=1
sin
2
(
a
)
+
1
(
1
+
tan
2
(
a
)
)
=
1
tan(a)= 5/9 ,b=6
tan
(
a
)
=
5
9
,
b
=
6
sin^3(x)sin^2(x)sin(x)=0
sin
3
(
x
)
sin
2
(
x
)
sin
(
x
)
=
0
2cos^2(x)+1=cos^2(x)
2
cos
2
(
x
)
+
1
=
cos
2
(
x
)
sin^2(x)cos^2(x)=((1-cos^4(x)))/8
sin
2
(
x
)
cos
2
(
x
)
=
(
1
−
cos
4
(
x
)
)
8
sin^3(x)+sin(x)=2sin^{22}(x)
sin
3
(
x
)
+
sin
(
x
)
=
2
sin
2
2
(
x
)
(1+tan^2(x))/(1+sec(x))=sec(x)
1
+
tan
2
(
x
)
1
+
sec
(
x
)
=
sec
(
x
)
-sin^2(x)+2cos(x)-2=0
−
sin
2
(
x
)
+
2
cos
(
x
)
−
2
=
0
sin(5x-1)= 4/5
sin
(
5
x
−
1
)
=
4
5
sin^2(x)= 1/36
sin
2
(
x
)
=
1
3
6
tan(x)=31
tan
(
x
)
=
3
1
sin^4(x)+cos^2(x)=2
sin
4
(
x
)
+
cos
2
(
x
)
=
2
5tan(x)=15cot(x)
5
tan
(
x
)
=
1
5
cot
(
x
)
solvefor x,arctan(x)=arctan(y)
solvefor
x
,
arctan
(
x
)
=
arctan
(
y
)
cos(x+10)-cos(x+90)=1
cos
(
x
+
1
0
◦
)
−
cos
(
x
+
9
0
◦
)
=
1
2cos(x)-2sqrt(3)*sin(x)=sqrt(8)
2
cos
(
x
)
−
2
√
3
·
sin
(
x
)
=
√
8
((cot(x)-sqrt(3)))/((2sin(x)+1))=0
(
cot
(
x
)
−
√
3
)
(
2
sin
(
x
)
+
1
)
=
0
sin^2(x)+3sin(x)-1=0
sin
2
(
x
)
+
3
sin
(
x
)
−
1
=
0
tan(x)-3^{1/2}=0
tan
(
x
)
−
3
1
2
=
0
(1+(2sin(x)))/((cos(x)))=0
1
+
(
2
sin
(
x
)
)
(
cos
(
x
)
)
=
0
(sin^2(a))/2 =(1-cos(a))/2
sin
2
(
a
)
2
=
1
−
cos
(
a
)
2
(cot^2(x))/2 =3
cot
2
(
x
)
2
=
3
sin(x-30)=0.7
sin
(
x
−
3
0
◦
)
=
0
.
7
<= sqrt(3)*cos(x)-sin(x)=0
≤
√
3
·
cos
(
x
)
−
sin
(
x
)
=
0
tan^2(x)+sec^2(x)=3
tan
2
(
x
)
+
sec
2
(
x
)
=
3
4sin^2(x)-6cos^2(x)=0
4
sin
2
(
x
)
−
6
cos
2
(
x
)
=
0
sin(60-a)=0.598
sin
(
6
0
◦
−
a
)
=
0
.
5
9
8
sin(a)=0.143
sin
(
a
)
=
0
.
1
4
3
sin(x)=cos^2(x)+1
sin
(
x
)
=
cos
2
(
x
)
+
1
sin(a)=1.25
sin
(
a
)
=
1
.
2
5
(1+(tan^2(a))/1+cot^2(a))=tan^2(a)
(
1
+
tan
2
(
a
)
1
+
cot
2
(
a
)
)
=
tan
2
(
a
)
2cos(x)+1=sin^2(x)
2
cos
(
x
)
+
1
=
sin
2
(
x
)
4cos^2(x)-11cos(x)+7=0
4
cos
2
(
x
)
−
1
1
cos
(
x
)
+
7
=
0
sqrt(3)tan(x)+2sec(x)=1
√
3
tan
(
x
)
+
2
sec
(
x
)
=
1
cos(a)=0.14
cos
(
a
)
=
0
.
1
4
(1+cos^2(x))/(sin^2(x))= 1/(sin^2(x))
1
+
cos
2
(
x
)
sin
2
(
x
)
=
1
sin
2
(
x
)
7sin(a)= 1/11
7
sin
(
a
)
=
1
1
1
tan(x)=2,x+y=135
tan
(
x
)
=
2
,
x
+
y
=
1
3
5
tan(x/2)+cos(x)=1
tan
(
x
2
)
+
cos
(
x
)
=
1
sinh(z)=-1
sinh
(
z
)
=
−
1
1+cos^2(a)=2cos^2(a)
1
+
cos
2
(
a
)
=
2
cos
2
(
a
)
sin(x)= 15/18
sin
(
x
)
=
1
5
1
8
cos(5x)=cos(5+x)
cos
(
5
x
)
=
cos
(
5
+
x
)
6cos^2(x)-7cos(x)-5=0
6
cos
2
(
x
)
−
7
cos
(
x
)
−
5
=
0
cos(x)=(-3)/(5sin^2(x))
cos
(
x
)
=
−
3
5
sin
2
(
x
)
5cos^2(x)-12sin^2(x)=13
5
cos
2
(
x
)
−
1
2
sin
2
(
x
)
=
1
3
cos^2(x)-0.5cos(x)=0
cos
2
(
x
)
−
0
.
5
cos
(
x
)
=
0
5sin(x)cos(x)=2cos(x)
5
sin
(
x
)
cos
(
x
)
=
2
cos
(
x
)
sin(x)=cos^3(x)
sin
(
x
)
=
cos
3
(
x
)
a=((1+sin^2(x)))/((1-sin^2(x)))
a
=
(
1
+
sin
2
(
x
)
)
(
1
−
sin
2
(
x
)
)
solvefor x,b*f=sin^3(x)
solvefor
x
,
b
·
f
=
sin
3
(
x
)
2sin^2(x)+sin^3(x)-1=0
2
sin
2
(
x
)
+
sin
3
(
x
)
−
1
=
0
2cos^2(x)=3cos(x)-1
2
cos
2
(
x
)
=
3
cos
(
x
)
−
1
sin^2(x)-4sin(x)+4=0
sin
2
(
x
)
−
4
sin
(
x
)
+
4
=
0
3cos^2(x)-10cos(x)+3=0
3
cos
2
(
x
)
−
1
0
cos
(
x
)
+
3
=
0
(m+1)sin(x)+2-m=0
(
m
+
1
)
sin
(
x
)
+
2
−
m
=
0
sin^5(x)+sin(x)+2sin^2(x)=1
sin
5
(
x
)
+
sin
(
x
)
+
2
sin
2
(
x
)
=
1
(2cos(x)-1)*(2sin(x)+1)=3-4sin^2(x)
(
2
cos
(
x
)
−
1
)
·
(
2
sin
(
x
)
+
1
)
=
3
−
4
sin
2
(
x
)
r=(2a)/((1+cos(x)))
r
=
2
a
(
1
+
cos
(
x
)
)
cos^3(x)+cos^2(x)+cos(x)+1=0
cos
3
(
x
)
+
cos
2
(
x
)
+
cos
(
x
)
+
1
=
0
(cos^4(x))/3 =sin^2(x)
cos
4
(
x
)
3
=
sin
2
(
x
)
sin^3(x)cos(x)-sin^2(x)=0
sin
3
(
x
)
cos
(
x
)
−
sin
2
(
x
)
=
0
sin^2(x)+sin^4(x)=0
sin
2
(
x
)
+
sin
4
(
x
)
=
0
cos^2(45-a)-sin^2(45-a)=sin^2(a)
cos
2
(
4
5
◦
−
a
)
−
sin
2
(
4
5
◦
−
a
)
=
sin
2
(
a
)
sin^2(2x)-cos^2(2x)=0
sin
2
(
2
x
)
−
cos
2
(
2
x
)
=
0
cos^2(x)cos(x)=0
cos
2
(
x
)
cos
(
x
)
=
0
2cos(x)=-3
2
cos
(
x
)
=
−
3
8sec(x)-3tan^2(x)=7
8
sec
(
x
)
−
3
tan
2
(
x
)
=
7
sin^2(6x)+sin^2(3x)=0
sin
2
(
6
x
)
+
sin
2
(
3
x
)
=
0
1/((2-sin(x)))=sin(x)
1
(
2
−
sin
(
x
)
)
=
sin
(
x
)
6sin(x)-3sin^2(x)=3-cos^2(x)
6
sin
(
x
)
−
3
sin
2
(
x
)
=
3
−
cos
2
(
x
)
1-tan^2(x)=a^2+b^2
1
−
tan
2
(
x
)
=
a
2
+
b
2
4sin(x)-4sin^3(x)=0
4
sin
(
x
)
−
4
sin
3
(
x
)
=
0
5tan^4(x)-10tan^2(x)+1=0
5
tan
4
(
x
)
−
1
0
tan
2
(
x
)
+
1
=
0
6tan(x)=8
6
tan
(
x
)
=
8
1
..
339
340
341
342
343
..
345
