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常见 三角函数 问题
tan(θ)= 4/3 ,cos(θ)<0
tan
(
θ
)
=
4
3
,
cos
(
θ
)
<
0
cot(x)=(sin(x))/(cos(x))
cot
(
x
)
=
sin
(
x
)
cos
(
x
)
0.6=(cosh(0.2m))/(cosh(0.4m))
0
.
6
=
cosh
(
0
.
2
m
)
cosh
(
0
.
4
m
)
12cos(2x)+5sin(x)-9=0
1
2
cos
(
2
x
)
+
5
sin
(
x
)
−
9
=
0
sin(x)= 4/8
sin
(
x
)
=
4
8
csc(a)=-1
csc
(
a
)
=
−
1
sin^2(x/2)= 1/(2-(1/2 sin(x/2)))
sin
2
(
x
2
)
=
1
2
−
(
1
2
sin
(
x
2
)
)
cos(x)-cos(x+pi/4)=0
cos
(
x
)
−
cos
(
x
+
π
4
)
=
0
cos(x)=0.7597
cos
(
x
)
=
0
.
7
5
9
7
cos(3x)=-3cos(x)
cos
(
3
x
)
=
−
3
cos
(
x
)
cos(x)= 280/2000
cos
(
x
)
=
2
8
0
2
0
0
0
4cos(θ)=sqrt(2)+2cos(θ)
4
cos
(
θ
)
=
√
2
+
2
cos
(
θ
)
solvefor x,T(6)=3.15cos(pi/6 x)+19.15
solvefor
x
,
T
(
6
)
=
3
.
1
5
cos
(
π
6
x
)
+
1
9
.
1
5
3tan^2(x)=1,-pi<= x<= pi
3
tan
2
(
x
)
=
1
,
−
π
≤
x
≤
π
cos(2t)-cos(t)=0.5
cos
(
2
t
)
−
cos
(
t
)
=
0
.
5
0=-6csc(x)cot(x)
0
=
−
6
csc
(
x
)
cot
(
x
)
0.08=0.12cos^2(3.922t)
0
.
0
8
=
0
.
1
2
cos
2
(
3
.
9
2
2
t
)
(15)/(sin(32))=(12)/(sin(b))
1
5
sin
(
3
2
◦
)
=
1
2
sin
(
b
)
(sin(x))/(25)=(sin(125))/(165.6)
sin
(
x
)
2
5
=
sin
(
1
2
5
◦
)
1
6
5
.
6
2cos(3θ)-1=0
2
cos
(
3
θ
)
−
1
=
0
cos(4x)=cos(8x)
cos
(
4
x
)
=
cos
(
8
x
)
cos(2x)-cos(x)=2
cos
(
2
x
)
−
cos
(
x
)
=
2
4sin(2x)+2sqrt(3)=0
4
sin
(
2
x
)
+
2
√
3
=
0
solvefor x,3=18cos(x)
solvefor
x
,
3
=
1
8
cos
(
x
)
solvefor x,2sin((pi(x-2))/6)=1
solvefor
x
,
2
sin
(
π
(
x
−
2
)
6
)
=
1
(1-sin(x))(1-sin(x))=cos^2(x)
(
1
−
sin
(
x
)
)
(
1
−
sin
(
x
)
)
=
cos
2
(
x
)
2cos(x)=cos^2(x)-1
2
cos
(
x
)
=
cos
2
(
x
)
−
1
2sin(v)csc(v)-csc(v)=4sin(v)-2
2
sin
(
v
)
csc
(
v
)
−
csc
(
v
)
=
4
sin
(
v
)
−
2
2cos(2x)=4cos(x)
2
cos
(
2
x
)
=
4
cos
(
x
)
(sin(42))/(22)=(sin(B))/(12)
sin
(
4
2
◦
)
2
2
=
sin
(
B
)
1
2
sin(θ)= 16/14
sin
(
θ
)
=
1
6
1
4
tan(θ)= 83/47
tan
(
θ
)
=
8
3
4
7
solvefor x,2sin(x)-cos(x)sin(x)=0
solvefor
x
,
2
sin
(
x
)
−
cos
(
x
)
sin
(
x
)
=
0
5=5sin(4θ)
5
=
5
sin
(
4
θ
)
cos(x)=(cos(x))/(csc(x))
cos
(
x
)
=
cos
(
x
)
csc
(
x
)
cos(θ)= 1/(sqrt(1^2+(4)^2+8^2))
cos
(
θ
)
=
1
√
1
2
+
(
4
)
2
+
8
2
2+3cot^2(x)-3csc(x)=5
2
+
3
cot
2
(
x
)
−
3
csc
(
x
)
=
5
-2=-2+tan(θ)
−
2
=
−
2
+
tan
(
θ
)
cos(A)=0.65
cos
(
A
)
=
0
.
6
5
sin(3x-pi/4)=(sqrt(2))/2
sin
(
3
x
−
π
4
)
=
√
2
2
sin(2θ)=(-3)/4 ,(3pi)/2 <= 2θ<= 2pi
sin
(
2
θ
)
=
−
3
4
,
3
π
2
≤
2
θ
≤
2
π
3sqrt(cot(x-10))=4
3
√
cot
(
x
−
1
0
◦
)
=
4
2.4638cos(x)=2.5843
2
.
4
6
3
8
cos
(
x
)
=
2
.
5
8
4
3
tan^2(x)=2tan(x)+2tan^3(x)
tan
2
(
x
)
=
2
tan
(
x
)
+
2
tan
3
(
x
)
solvefor t,cos(wt+k)=(20)/((2*pi*f)^2)
solvefor
t
,
cos
(
wt
+
k
)
=
2
0
(
2
·
π
·
f
)
2
0=-cos(x)(2sin(x)+3)
0
=
−
cos
(
x
)
(
2
sin
(
x
)
+
3
)
28cos(t)=20,0<= t<360
2
8
cos
(
t
)
=
2
0
,
0
◦
≤
t
<
3
6
0
◦
8tan(x/2)+8cos(x)tan(x/2)=1
8
tan
(
x
2
)
+
8
cos
(
x
)
tan
(
x
2
)
=
1
sin(a)=0.5937
sin
(
a
)
=
0
.
5
9
3
7
tan(x)= 18/25
tan
(
x
)
=
1
8
2
5
sin^2(x)= 3/2
sin
2
(
x
)
=
3
2
1.5=1+sin(x/3)
1
.
5
=
1
+
sin
(
x
3
)
sqrt(3)*tan(x)+2sec(x)=1
√
3
·
tan
(
x
)
+
2
sec
(
x
)
=
1
cos^2(a)=2cos^2(a)-1
cos
2
(
a
)
=
2
cos
2
(
a
)
−
1
tan(3b+14)=cot(5b+4)
tan
(
3
b
+
1
4
)
=
cot
(
5
b
+
4
)
(2sin(x)-cos(x))(1+cos(x))=sin^2(x)
(
2
sin
(
x
)
−
cos
(
x
)
)
(
1
+
cos
(
x
)
)
=
sin
2
(
x
)
sec^2(x)+2tan^2(x)=2
sec
2
(
x
)
+
2
tan
2
(
x
)
=
2
sin(x^2-2x)=0
sin
(
x
2
−
2
x
)
=
0
8sin^2(x)+4cos^2(x)=7
8
sin
2
(
x
)
+
4
cos
2
(
x
)
=
7
10cos^2(x)+cos(x)=11sin^2(x)-9
1
0
cos
2
(
x
)
+
cos
(
x
)
=
1
1
sin
2
(
x
)
−
9
sin(6.5x+2.5)=0.0851
sin
(
6
.
5
x
+
2
.
5
)
=
0
.
0
8
5
1
1-tan(x)=(-1)/3
1
−
tan
(
x
)
=
−
1
3
sin(x/3)=cos(x/2)
sin
(
x
3
)
=
cos
(
x
2
)
cos(x)=(cot^2(x))/(csc^2(x))
cos
(
x
)
=
cot
2
(
x
)
csc
2
(
x
)
2tan^2(x)-3cot^2(x)=5
2
tan
2
(
x
)
−
3
cot
2
(
x
)
=
5
solvefor x,13y=cos^4(1-2x)
solvefor
x
,
1
3
y
=
cos
4
(
1
−
2
x
)
cos(x)+cos^2(x)+cos^3(x)=0
cos
(
x
)
+
cos
2
(
x
)
+
cos
3
(
x
)
=
0
cos(x)-sin(x)= 1/((sin(x)))-1/((cos(x)))
cos
(
x
)
−
sin
(
x
)
=
1
(
sin
(
x
)
)
−
1
(
cos
(
x
)
)
sin^2(x)+cos^5(x)=2
sin
2
(
x
)
+
cos
5
(
x
)
=
2
16=4+9-12cos(x)
1
6
=
4
+
9
−
1
2
cos
(
x
)
tanh(z)+2=0
tanh
(
z
)
+
2
=
0
cos^2(a)= 2/(3sin(a))
cos
2
(
a
)
=
2
3
sin
(
a
)
5cos(5x)=2
5
cos
(
5
x
)
=
2
4sin(x)-sin^3(x)-1=0
4
sin
(
x
)
−
sin
3
(
x
)
−
1
=
0
1-tan(a)=(-1)/3
1
−
tan
(
a
)
=
−
1
3
tan^2(x)+cos^2(x)-1=0
tan
2
(
x
)
+
cos
2
(
x
)
−
1
=
0
cot^3(x)+cot(x)=0
cot
3
(
x
)
+
cot
(
x
)
=
0
21+18cos(x)=16(1-cos^2(x))
2
1
+
1
8
cos
(
x
)
=
1
6
(
1
−
cos
2
(
x
)
)
sin(2a+10)=cos(3a-20)
sin
(
2
a
+
1
0
)
=
cos
(
3
a
−
2
0
)
b= 3/((cot(x)))
b
=
3
(
cot
(
x
)
)
4sin^2(x)+cos(x)+1=0
4
sin
2
(
x
)
+
cos
(
x
)
+
1
=
0
(cot^2(x))-csc(x)=1
(
cot
2
(
x
)
)
−
csc
(
x
)
=
1
solvefor x,u=arctan(x/y)
solvefor
x
,
u
=
arctan
(
x
y
)
4cos^2(2x-1)=1
4
cos
2
(
2
x
−
1
)
=
1
sin^2(x)-2cos^2(x)+cos^2(x)=0
sin
2
(
x
)
−
2
cos
2
(
x
)
+
cos
2
(
x
)
=
0
sqrt(3)*sin(x)=cos(x)
√
3
·
sin
(
x
)
=
cos
(
x
)
sin^{22}(x)sin^3(x)+6=18
sin
2
2
(
x
)
sin
3
(
x
)
+
6
=
1
8
d^2+4d+4=sin(x)
d
2
+
4
d
+
4
=
sin
(
x
)
8cos(a)-15sin(a)=0
8
cos
(
a
)
−
1
5
sin
(
a
)
=
0
tan(t)= 3/(tan(t))
tan
(
t
)
=
3
tan
(
t
)
tan(-x)=tan(2x+1)
tan
(
−
x
)
=
tan
(
2
x
+
1
)
(2cos(x)-sin(x))(1+sin(x))=cos^2(x)
(
2
cos
(
x
)
−
sin
(
x
)
)
(
1
+
sin
(
x
)
)
=
cos
2
(
x
)
sin(6x)cos(9x)-cos(6x)sin(9x)=-0.4
sin
(
6
x
)
cos
(
9
x
)
−
cos
(
6
x
)
sin
(
9
x
)
=
−
0
.
4
sin^2(x)=2tan^2(x)
sin
2
(
x
)
=
2
tan
2
(
x
)
cos^3(x)=cos(2x+x)
cos
3
(
x
)
=
cos
(
2
x
+
x
)
solvefor x,(d^2-3d+2)y=sin(e^x)
solvefor
x
,
(
d
2
−
3
d
+
2
)
y
=
sin
(
e
x
)
cos(6x)+cos(2x)=0
cos
(
6
x
)
+
cos
(
2
x
)
=
0
2sin^2(45-a)=1-sin^2(a)
2
sin
2
(
4
5
◦
−
a
)
=
1
−
sin
2
(
a
)
(2cos(a)+1)(2cos(a)-1)=2cos^2(a)+1
(
2
cos
(
a
)
+
1
)
(
2
cos
(
a
)
−
1
)
=
2
cos
2
(
a
)
+
1
tan^2(x)cot(x)=1
tan
2
(
x
)
cot
(
x
)
=
1
1
..
336
337
338
339
340
..
345
